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Re: [tuning] constant structure

🔗Kraig Grady <kraiggrady@anaphoria.com>

3/6/2000 7:06:39 PM

Dan!
A scale formed of the superposition of a single interval would form
MOS's. Like a pythag. diatonic. A scale like , in example, a JI diatonic
would be a constant structure. all the 5/4 are 2 steps, the 4/3 are 3
steps, the 9/8 are one steps etc. The thing to remember is that a scale in
Wilson's term is a melodic structure not a harmonic onethat has its own
integrity. As far as subsets of an ET yes these can be Constant Structures.

"D.Stearns" wrote:

> From: "D.Stearns" <STEARNS@CAPECOD.NET>
>
> Earlier I wrote,
>
> > OK, let me see if I've got this... so say a scale like the 7-tone 3L
> & 4s, this would be strictly proper and a constant structure if it
> were constructed from a chain of intervals > 2/7ths of an octave and <
> 3/10ths of an octave, [etc.]
>
> Just to make sure I'm clear, when I say "if it were constructed from a
> chain of intervals" that is some condition, I mean a chain of
> intervals of a single size that meets that condition.
>
> Dan
>
>

-- Kraig Grady
North American Embassy of Anaphoria island
www.anaphoria.com

🔗D.Stearns <STEARNS@CAPECOD.NET>

3/7/2000 2:01:09 PM

[Kraig Grady:]
>A scale formed of the superposition of a single interval would form
MOS's. Like a pythag. diatonic. A scale like , in example, a JI
diatonic would be a constant structure.

But is the MOS, Pythagorean diatonic also a constant structure? From
the definition you gave in Joe's tuning dictionary I would think so,
but in the explanation here you seem to me to be using the first as a
an example separate from the second, and this seems to be saying that
the first is not an example of a CS, but that the second (the syntonic
diatonic) is...(?) so I guess I'm still slightly confused on the exact
meaning here!

Dan

🔗Paul H. Erlich <PERLICH@ACADIAN-ASSET.COM>

3/7/2000 1:35:57 PM

Dan-

It would appear that all MOSs are indeed CS but calling an MOS a CS would be
like calling a diamond bracelet a "carbon bracelet".

-Paul

🔗D.Stearns <STEARNS@CAPECOD.NET>

3/7/2000 4:57:09 PM

[Paul H. Erlich:]
>It would appear that all MOSs are indeed CS but calling an MOS a CS
would be like calling a diamond bracelet a "carbon bracelet".

Yes, that analogy works for me too, but from the way things were being
explained I just wasn't sure... perhaps a bit of a clarification like
that at Joe's Dictionary would help others who might be confused on
the same point.

Dan

🔗Kraig Grady <kraiggrady@anaphoria.com>

3/7/2000 2:59:31 PM

Dan!
I guess you could call an MOS a constant structure (Paul's
Diamond/carbon analogy is very good). The idea can be seen as an MOS
produces certain keyboard mappings that ccan serve as a template for scales
involving the superposition of more than i interval

"D.Stearns" wrote:

> From: "D.Stearns" <STEARNS@CAPECOD.NET>
>
> [Kraig Grady:]
> >A scale formed of the superposition of a single interval would form
> MOS's. Like a pythag. diatonic. A scale like , in example, a JI
> diatonic would be a constant structure.
>
> But is the MOS, Pythagorean diatonic also a constant structure? From
> the definition you gave in Joe's tuning dictionary I would think so,
> but in the explanation here you seem to me to be using the first as a
> an example separate from the second, and this seems to be saying that
> the first is not an example of a CS, but that the second (the syntonic
> diatonic) is...(?) so I guess I'm still slightly confused on the exact
> meaning here!
>
> Dan
>

-- Kraig Grady
North American Embassy of Anaphoria island
www.anaphoria.com

🔗D.Stearns <STEARNS@CAPECOD.NET>

3/7/2000 8:50:52 PM

[Kraig Grady:]
>I guess you could call an MOS a constant structure (Paul's
Diamond/carbon analogy is very good).

Yes, thanks Kraig and Paul, I got it... I think the problem, or my
confusion, arose from the two definitions at Joe's Dictionary
(including your cryptically curt one!)... in my case (which could just
be me) they were not exactly helpful as shall we say well defined
definitions, but as usual, the back and forth of technical particulars
here at the TD has made it clear for me, so again, thanks.

Dan