Bendeler

there are also ratios by Bendeler
http://groenewald-berlin.de/text/text_T086.html

in 5ths:
the three Quinten c-g, g-d und b-f# got each reduced about
the amount of ~7.820 cents.

(f) 4/3 x 3/2 : 2 = 1/1 (c)
(b) 16/9 x 3/2 : 2 = 4/3 (f)
(es) 32/27 x 3/2 : = 16/9 (b)
(as) 128/81 x 3/2 : 2 = 32/27 (es)
(des) 256/243 x 3/2 = 128/81 (as)
(ges) 1024/729 x 3/2 : 2 = 256/243 (des)
(h) 2024/1089 x 3/2 : 243/242 : 2 = 1024/729 (ges)
(e) 4096/3267 x 3/2 = 2024/1089 (h)
(a) 16384/9801 x 3/2 : 2 = 4096/3267 (e)
(d) 32768/29403 x 3/2 : = 16384/9801 (a)
(g) 65536/43923 x 3/2 : 243/242 : 2 = 32768/29403 (d)
(c) 1/1 x 3/2 : 32x114/217 = 65536/43923 (g)

that yiels in chromatically ascending order

c = 2/1 12.0 2/1 1200.000 Cent
H = 1089/1024 10.935 2048/1089 1093.454 Cent
B = 9/8 9.961 16/9 996.090 Cent
A = 9801/8192 8.895 16384/9801 889.544 Cent
Gs = 81/64 7.922 128/81 792.180 Cent
G = 87846/65536 6.928 65536/43923 694.773 Cent
Fs = 729/512 5.883 1024/729 588.270 Cent
F = 3/2 4.980 4/3 498.045 Cent
E = 3267/2048 3.915 4096/3267 391.499 Cent
Ds = 27/16 2.941 32/27 294.135 Cent D = 29403/16384 1.876 32768/29403 187.589Cent
Cs = 243/128 0.902 256/243 90.225 Cent
C = - 0.0 1/1 0.000 Cent

!Bendeler.scl
Bendeler, as quoted by Toepfer, compiled by A.Sparschuh
12
!
256/243 ! C#
32768/29403 ! D
32/27 ! Eb
4096/3267 ! E
4/3 ! F
1024/729 ! F#
131072/87846 ! G
128/81 ! G#
16384/9801 ! A
16/9 ! Bb
2048/1089 ! B
2/1
!
!(EOF]

bye
Andy