Inverse series for neutral third

I haven't been following the discussion as closely as I should, but taking a
starting point for the neutral third as the square root of 3/2 or 1.2247, I
get the following short multiplication inverse series:

12247/10000 122470000 1.224700
27/22 594 1.227273
16/13 208 1.230769
11/9 99 1.222222
6/5 30 1.200000
5/4 20 1.250000

BTW, the multiplication inverse program I posted yesterday seems to work fine
on numbers that aren't mutually prime, much to my surprise.

Marion