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f + F and WFS/MOS

🔗Dan Stearns <stearns@capecod.net>

1/4/1999 6:23:06 PM

When mapped onto a circle of clockwise [(d � O) x F] integer F�s, and
counterclockwise [(d � O) x f] integer f�s (+ 2 + 2 - 5 + 2 + 2 + 2 - 5),
all equidistant divisions of the octave inside the boarders of f and F:

1f, 1F
2f, 1F + 1f, 2F
3f, 1F + 2f, 2F + 1f, 3F
4f, 1F + 3f, 2F + 2f, 3F + 1f, 4F
5f, 1F + 4f, 2F + 3f, 3F + 2f, 4F + 1f, fF
6f, 1F + 5f, 2F + 4f, 3F + 3f, 4F + 2f, 5F + 1f, 6F
Ff

will create a diatonic heptad (1�2�3�4�5�6�7�8 @ + w + w + h + w + w + w +
h) constructed of (only) two sizes of diatonic seconds where w > h, and h >
0.

1, 2, 3, 4, 6, 8, 9, 11, 13, 16, 18, and 23 (@ 1/0, 1/1, 2/1, 2/2, 4/2, 5/3,
5/4, 6/5, 8/5, 9/7, 11/7, and 13/10), would be the twelve (and only)
equidistant divisions of the octave comprised of an entire intervalic
inventory that lies outside this (1/35th of an octave) �F/f aperture��

If F < 4/7ths of an octave; h > w, and if F > 3/5ths of an octave; h = -n.

5, 7, 10, 14, 15, 21, 20, 28, 25, 35, 30, and 35 (@ 1f, 1F, 2f, 2F, 3f, 4f,
3F, 5f, 4F, 6f, Ff and fF), would be the [twelve] equidistant divisions of
the octave that define the parameters of the F/f aperture�

fh = 0 and Fw = Fh.

12, 17, 19, 22, 24, 26, 27, 29, 31, 33, 32, and 34 (@ 1F + 1f, 1F + 2f, 2F +
1f, 1F + 3f, 2F + 2f, 3F + 1f, 1F + 4f, 2F + 3f, 3F + 2f, 4F + 1f, 1F + 5f,
and 2F + 4f) would be the twelve equidistant divisions of the octave that
lie inside the (MOS stable?) borders of this F/f aperture where w > h, and h
> 0�

All equidistant divisions of the octave after f X F (35 EDO) have a
fifth/fourth inside of the F/f parameters�

Therefore all equidistant divisions of the octave after fF mapped onto a
circle of clockwise [(d � O) x F] integer F�s and counterclockwise [(d � O)
x f] integer f�s (+ 2 + 2 - 5 + 2 + 2 + 2 - 5), will have a diatonic heptad
(1�2�3�4�5�6�7�8 @ + w + w + h + w + w + w + h) where w > h, and h > 0.

Respectfully,
Dan Stearns