Yahoo Tuning Groups Ultimate Backup tuning Resolved problem

To the tuning list,

The new appearance of the progression differs from the original after cancelling the last 12 cells from # 613 to # 624, that is the pythagorean comma. All the original frequency cells continue their work. Highest frequency cell of each of the new twelve sections coincide with the last cell of each subsection given in the book.

A twelve tone equal division scale with piagui K and 256/243 tone intervals emerged and the frequency coincidences when any cell is multiplied by 4/3 or 3/2 seem to work. Tomorrow I will probably send enough information.

Mario

April, 10

🔗Mike Battaglia <battaglia01@...>

I don't get it. Does the progression now repeat every 2/1?

-Mike

On Tue, Apr 10, 2012 at 4:45 PM, Mario Pizarro <piagui@...> wrote:
> To the tuning list,
>
> The new appearance of the progression differs from the original after
> cancelling the last 12 cells from # 613 to # 624, that is the pythagorean
> comma. All the original frequency cells continue their work. Highest
> frequency cell of each of the new twelve sections coincide with the last
> cell of each subsection given in the book.
>
> A twelve tone equal division scale with piagui K and 256/243 tone intervals
> emerged and the frequency coincidences when any cell is multiplied by 4/3 or
> 3/2 seem to work. Tomorrow I will probably send enough information.
>
> Mario
>
> April, 10

🔗Mario Pizarro <piagui@...>

Mike,

When deriving a correction to the double frequency obtained when a cell is multiplied by 4/3, anounced by Keenan, during the investigation eleven digit numbers appeared some times on the computer screen. Curiously they were cell frequencies so I decided to take note of five of these frequencies and complete a scale these way:

1, (9/8)^1/2, 9/8, 1.19324269325229, 81/64, 1.34239802990883, 2^1/2, 1.48987107805559, 1.58024691358023, 1.67610496281253, 1.77777777777, 1.88561808316409, 2.

I completed the digits by using the info given in my book.

Checking the tone intervals I found that there are two types: K = 1.06066017178 and 256/243.

The range is from 1 to 2, the former pythagorean comma was cancelled. The number of cells of each of the 12 section follows:

52(C#), 52(D), 52, .......(five intervals of 52 cells each).....46, 46,.... (five intervals of 52 cells each).

It is and endless progression. You can get 4, 8, 16, ...... etc.

The cell sequence is the same but its distribution differs from the original.

This time I think the 4/3 and 3/2 cell products is going to work correctly.

Mario

April, 10
<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<.
----- Original Message ----- From: "Mike Battaglia" <battaglia01@...>
To: <tuning@yahoogroups.com>
Sent: Tuesday, April 10, 2012 3:48 PM
Subject: [tuning] Re: Resolved problem

I don't get it. Does the progression now repeat every 2/1?

-Mike

On Tue, Apr 10, 2012 at 4:45 PM, Mario Pizarro <piagui@...> wrote:
> To the tuning list,
>
> The new appearance of the progression differs from the original after
> cancelling the last 12 cells from # 613 to # 624, that is the pythagorean
> comma. All the original frequency cells continue their work. Highest
> frequency cell of each of the new twelve sections coincide with the last
> cell of each subsection given in the book.
>
> A twelve tone equal division scale with piagui K and 256/243 tone > intervals
> emerged and the frequency coincidences when any cell is multiplied by 4/3 > or
> 3/2 seem to work. Tomorrow I will probably send enough information.
>
> Mario
>
> April, 10

------------------------------------

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🔗Mike Battaglia <battaglia01@...>

I still don't get it. Does the progression now repeat every 2/1?

-Mike

On Tue, Apr 10, 2012 at 7:52 PM, Mario Pizarro <piagui@...> wrote:
> Mike,
>
> When deriving a correction to the double frequency obtained when a cell is
> multiplied by 4/3, anounced by Keenan, during the investigation eleven digit
> numbers appeared some times on the computer screen. Curiously they were cell
> frequencies so I decided to take note of five of these frequencies and
> complete a scale these way:
>
> 1, (9/8)^1/2, 9/8, 1.19324269325229, 81/64, 1.34239802990883, 2^1/2,
> 1.48987107805559, 1.58024691358023, 1.67610496281253, 1.77777777777,
> 1.88561808316409, 2.
>
> I completed the digits by using the info given in my book.
>
> Checking the tone intervals I found that there are two types: K =
> 1.06066017178 and 256/243.
>
> The range is from 1 to 2, the former pythagorean comma was cancelled. The
> number of cells of each of the 12 section follows:
>
> 52(C#), 52(D), 52, .......(five intervals of 52 cells each).....46, 46,....
> (five intervals of 52 cells each).
>
> It is and endless progression. You can get 4, 8, 16, ...... etc.
>
> The cell sequence is the same but its distribution differs from the
> original.
>
> This time I think the 4/3 and 3/2 cell products is going to work correctly.
>
> Mario

🔗Keenan Pepper <keenanpepper@...>

--- In tuning@yahoogroups.com, "Mario Pizarro" <piagui@...> wrote:
>
> Mike,
>
> When deriving a correction to the double frequency obtained when a cell is
> multiplied by 4/3, anounced by Keenan, during the investigation eleven digit
> numbers appeared some times on the computer screen. Curiously they were cell
> frequencies so I decided to take note of five of these frequencies and
> complete a scale these way:
>
> 1, (9/8)^1/2, 9/8, 1.19324269325229, 81/64, 1.34239802990883, 2^1/2,
> 1.48987107805559, 1.58024691358023, 1.67610496281253, 1.77777777777,
> 1.88561808316409, 2.
>
> I completed the digits by using the info given in my book.
>
> Checking the tone intervals I found that there are two types: K =
> 1.06066017178 and 256/243.
>
> The range is from 1 to 2, the former pythagorean comma was cancelled. The
> number of cells of each of the 12 section follows:
>
> 52(C#), 52(D), 52, .......(five intervals of 52 cells each).....46, 46,....
> (five intervals of 52 cells each).
>
> It is and endless progression. You can get 4, 8, 16, ...... etc.
>
> The cell sequence is the same but its distribution differs from the
> original.
>
> This time I think the 4/3 and 3/2 cell products is going to work correctly.

I think not, because the Fundamental Theorem of Arithmetic is still as true as ever.

Can we get a corrected version of the whole progression?

Keenan

🔗Mario Pizarro <piagui@...>

Keenan

> Can we get a corrected version of the whole progression?

I am working on that. As soon as can get it Iï¿½ll send it to you.

Mario

April, 11
-----------------------------------------------------
----- Original Message ----- From: "Keenan Pepper" <keenanpepper@...>
To: <tuning@yahoogroups.com>
Sent: Tuesday, April 10, 2012 10:11 PM
Subject: [tuning] Re: Resolved problem

> --- In tuning@yahoogroups.com, "Mario Pizarro" <piagui@...> wrote:
>>
>> Mike,
>>
>> When deriving a correction to the double frequency obtained when a cell >> is
>> multiplied by 4/3, anounced by Keenan, during the investigation eleven >> digit
>> numbers appeared some times on the computer screen. Curiously they were >> cell
>> frequencies so I decided to take note of five of these frequencies and
>> complete a scale these way:
>>
>> 1, (9/8)^1/2, 9/8, 1.19324269325229, 81/64, 1.34239802990883, 2^1/2,
>> 1.48987107805559, 1.58024691358023, 1.67610496281253, 1.77777777777,
>> 1.88561808316409, 2.
>>
>> I completed the digits by using the info given in my book.
>>
>> Checking the tone intervals I found that there are two types: K =
>> 1.06066017178 and 256/243.
>>
>> The range is from 1 to 2, the former pythagorean comma was cancelled. The
>> number of cells of each of the 12 section follows:
>>
>> 52(C#), 52(D), 52, .......(five intervals of 52 cells each).....46, >> 46,....
>> (five intervals of 52 cells each).
>>
>> It is and endless progression. You can get 4, 8, 16, ...... etc.
>>
>> The cell sequence is the same but its distribution differs from the
>> original.
>>
>> This time I think the 4/3 and 3/2 cell products is going to work >> correctly.
>
> I think not, because the Fundamental Theorem of Arithmetic is still as > true as ever.
>
> Can we get a corrected version of the whole progression?
>
> Keenan
>
>
>
>
> ------------------------------------
>
> You can configure your subscription by sending an empty email to one
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>
>
>
>

🔗martinsj013 <martinsj@...>

🔗Mario Pizarro <piagui@...>

Steve Martin S.

Steve,

Looking at the problem from other side, the progression exhibits a cyclical and continuous distribution and obeys the sequence 23, 52, 28-- 23, 52, 28 -- 23, 52, 28.........I just started wirh this posibility.

The first UU pair is placed at positions 23/24, .

+ 52 gives the second UU positions 75/76,

+ 28 gives 104 the end of the first cycle.

Again + 23 we have the pair on 104 + 23 = 127/128.

+52 gives the positions 179/180.

+28 ,end of second cycle ..... and so forth

This is a different type of attack. The main dificulty is the tiredness with numbers.

Mario
April 12

----- Original Message ----- From: "martinsj013" <martinsj@...>
To: <tuning@yahoogroups.com>
Sent: Thursday, April 12, 2012 6:11 AM
Subject: [tuning] Re: Resolved problem

--- In tuning@yahoogroups.com, "Mario Pizarro" <piagui@...> wrote:
> I am working on that. As soon as can get it Iï¿½ll send it to you.

re. "cell N+254" contains the value "cell N" x 4/3 - this would imply that the pattern repeats after 254 cells, but we know (don't we?) that the pattern repeats after 104 cells. The HCF of these two numbers is 2, so ...

Steve M.

------------------------------------

🔗Mike Battaglia <battaglia01@...>

On Thu, Apr 12, 2012 at 7:11 AM, martinsj013 <martinsj@...> wrote:
>
> --- In tuning@yahoogroups.com, "Mario Pizarro" <piagui@...> wrote:
> > I am working on that. As soon as can get it I´ll send it to you.
>
> re. "cell N+254" contains the value "cell N" x 4/3 - this would imply that
> the pattern repeats after 254 cells, but we know (don't we?) that the
> pattern repeats after 104 cells. The HCF of these two numbers is 2, so ...
>
> Steve M.

The pattern repeats after 104 cells? I thought it repeated after 612 cells?

Why won't Mario just tell me how many cells until everything repeats?

-Mike

🔗Charles Lucy <lucy@...>

See here for details:

http://www.lucytune.com/midi_and_keyboard/pitch_bend.html

Charles Lucy
lucy@...

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🔗Mario Pizarro <piagui@...>

Mike and Steve:

I would have liked to know the meaning of HCF-- (H..... Common Factor ?).

The pattern N + 254 repeats, it is correct, however the content of any of the repeated 104 cells contain different information whether you check the cell relations. The numbering system is also a repeatable system that is used in many ways, here, instead of the repeatable 104, in the numbering system we have the repeatable 1.

Even more, the progression do not contain repeated sections, it is an endless facility. The sun appears repeatebly too and nobody claims. This type of repeatable product shouldnï¿½t be critizised just for nature has imposed that music can live thanks to the existance of the periodicity effect.

About the progression, today I advanced towards a solution despite a long bone in my thorax was broken the past year and I knew that two weeks ago; a falldown, perhaps I will have to use a mechanical chair to get sure.

Mario

April, 12

<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<

----- Original Message ----- From: "Mike Battaglia" <battaglia01@...>
To: <tuning@yahoogroups.com>
Sent: Thursday, April 12, 2012 3:47 PM
Subject: Re: [tuning] Re: Resolved problem

On Thu, Apr 12, 2012 at 7:11 AM, martinsj013 <martinsj@...> wrote:
>
> --- In tuning@yahoogroups.com, "Mario Pizarro" <piagui@...> wrote:
> > I am working on that. As soon as can get it Iï¿½ll send it to you.
>
> re. "cell N+254" contains the value "cell N" x 4/3 - this would imply that
> the pattern repeats after 254 cells, but we know (don't we?) that the
> pattern repeats after 104 cells. The HCF of these two numbers is 2, so ...
>
> Steve M.

The pattern repeats after 104 cells? I thought it repeated after 612 cells?

Why won't Mario just tell me how many cells until everything repeats?

-Mike

------------------------------------

🔗martinsj013 <martinsj@...>

🔗Keenan Pepper <keenanpepper@...>

🔗Mario Pizarro <piagui@...>

Steve Martin S.

Steve,

Thanks for the "Highest" information.

EXTRA EXTRA-- The progression correction is going fine. Latest 5 days I was working on that about 3 hours a day, from now and on I do it 12 hours. You cannot imagine the importance of moving the UUï¿½s towards logic positions. It seems to be designed by top mathematicians and computers. He decided to be hidden in the space until I put my eyes on it.

The job is really complex

Mario

April, 14
<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<
----- Original Message ----- From: "martinsj013" <martinsj@...>
To: <tuning@yahoogroups.com>
Sent: Saturday, April 14, 2012 1:58 AM
Subject: [tuning] Re: Resolved problem

> --- In tuning@yahoogroups.com, "Mario Pizarro" <piagui@...> wrote:
>> Mike and Steve:
>> I would have liked to know the meaning of HCF-- (H..... Common Factor ?).
>
> Mario, yes, it is "Highest Common Factor". Steve M.
>
>
>
> ------------------------------------
>
> You can configure your subscription by sending an empty email to one
> of these addresses (from the address at which you receive the list):
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> tuning-help@yahoogroups.com - receive general help information.
> Yahoo! Groups Links
>
>
>
>

🔗Mario Pizarro <piagui@...>

Keenan Pepper

Keenan,.

The job is really complex

Mario

April, 14

<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<
----- Original Message ----- From: "Keenan Pepper" <keenanpepper@...>
To: <tuning@yahoogroups.com>
Sent: Saturday, April 14, 2012 9:27 AM
Subject: [tuning] Re: Resolved problem

> --- In tuning@yahoogroups.com, "martinsj013" <martinsj@...> wrote:
>>
>> --- In tuning@yahoogroups.com, "Mario Pizarro" <piagui@> wrote:
>> > Mike and Steve:
>> > I would have liked to know the meaning of HCF-- (H..... Common Factor >> > ?).
>>
>> Mario, yes, it is "Highest Common Factor". Steve M.
>
> The standard abbreviation for this is GCD, Greatest Common Divisor.
>
> Keenan
>
>
>
>
> ------------------------------------
>
> You can configure your subscription by sending an empty email to one
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>

🔗genewardsmith <genewardsmith@...>

--- In tuning@yahoogroups.com, "Mario Pizarro" <piagui@...> wrote:
>
> Keenan Pepper
>
> Keenan,.
>
> EXTRA EXTRA-- The progression correction is going fine. Latest 5 days I was
> working on that about 3 hours a day, from now and on I do it 12 hours. You
> cannot imagine the importance of moving the UU´s towards logic positions. It
> seems to be designed by top mathematicians and computers. He decided to be
> hidden in the space until I put my eyes on it.
>
> The job is really complex

Chances are it wouldn't be with more use of mathematics and computers, but unless people know what it is you are trying to accomplish no help can be expected from the rest of us.

🔗genewardsmith <genewardsmith@...>

--- In tuning@yahoogroups.com, "genewardsmith" <genewardsmith@...> wrote:

> > The job is really complex
>
> Chances are it wouldn't be with more use of mathematics and computers, but unless people know what it is you are trying to accomplish no help can be expected from the rest of us.
>

Comparing your musical cells to the first (five limit) column of this:

http://xenharmonic.wikispaces.com/Table+of+612edo+intervals

might be useful, Or it might not be. Not knowing what you are trying to do makes it impossible for me to say.