hi i am new student i have a problem

find the root of f(x)=x^3+30x-30

thanks

--- In tuning-math@y..., "nasnas_100" <nasnas_100@y...> wrote:

> hi i am new student i have a problem

> find the root of f(x)=x^3+30x-30

> thanks

what does this have to do with tuning?

Well . according to Derive, there are two complex roots and one real root:

x = -0.4848069410 - 5.541219478.i ; x = -0.4848069410 + 5.541219478.i ; x

= 0.9696138820

Now that I've given you the answer, your assignment is to look up the

formula (and there is one) for solving a cubic (which this is) equation and

post it to the list. Then tell us what this has to do with music / tuning.

-----Original Message-----

From: nasnas_100 [mailto:nasnas_100@yahoo.co.uk]

Sent: Friday, August 09, 2002 2:22 PM

To: tuning-math@yahoogroups.com

Subject: [tuning-math] find the root of the function

hi i am new student i have a problem

find the root of f(x)=x^3+30x-30

thanks

On Sat, 10 Aug 2002 13:59:06 -0700 "M. Edward Borasky"

<znmeb@aracnet.com> writes:

> Well . according to Derive, there are two complex roots and one real

> root:

>

> x = -0.4848069410 - 5.541219478.i ; x = -0.4848069410 +

> 5.541219478.i ; x

> = 0.9696138820

>

> Now that I've given you the answer, your assignment is to look up the

> formula (and there is one)

There's more than one, and solving it in radicals (as opposed to

Chebyshev radicals, for instance) isn't the neatest.