degrees of freedom in an "ultimate scale" search

Here's one way to count these up. The result is 12 bits or
about 4,000 different answers. Of course the actual number
of unique answers is likely to be far smaller. I suppose gold
medalists are another way to look at this.

prime limit (5-13) = 2 bits
temperament rank (1 or 2) = 1 bit
badness (Cangwu or logflat) = 1 bit
badness parameter = 3 bits*
TE or POTE error? = 1 bit
scale size = 4 bits**

* Cangwu thresholds in 4-cent (JND) bins from 2-30 cents
logflat complexity <= 6, 9, 15, 29, 59, 126, 277, or 612 notes/oct

** MOS series position with first MOS >= 5 notes/oct @ position 1

-Carl