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Odd-Limit and Dyadic-Odd-Limit Questions

🔗Ryan Avella <domeofatonement@yahoo.com>

2/20/2012 4:29:40 PM

Lets suppose that L(S) is the odd-limit of a chord S. DL(S) we will call the dyadic odd-limit of a chord S (the largest odd-limit of the multiset of dyads). For example, L(10:12:15) = 15, and DL(10:12:15) = 5.

Now I have some questions concerning chords with 3 or more notes:

1.) Is it possible to have an *otonal* chord where DL(S) < L(S)?
2.) Is it possible to have an *ambitonal* chord where DL(S) < L(S)?
3.) Is it possible to have a *utonal* chord where DL(S) = L(S)?

Mike told me that he thinks that case #1 and case #3 are impossible, but I don't know how to go about proving that. #2 is not possible for triads, but I don't know if it is possible for any other cases.

If anyone knows how to answer these questions, you are welcome to do so.

Ryan

🔗Mike Battaglia <battaglia01@gmail.com>

2/20/2012 5:09:56 PM

On Mon, Feb 20, 2012 at 7:29 PM, Ryan Avella <domeofatonement@yahoo.com>
wrote:
>
> Lets suppose that L(S) is the odd-limit of a chord S. DL(S) we will call
> the dyadic odd-limit of a chord S (the largest odd-limit of the multiset of
> dyads). For example, L(10:12:15) = 15, and DL(10:12:15) = 5.
>
> Now I have some questions concerning chords with 3 or more notes:
>
> 1.) Is it possible to have an *otonal* chord where DL(S) < L(S)?
> 2.) Is it possible to have an *ambitonal* chord where DL(S) < L(S)?
> 3.) Is it possible to have a *utonal* chord where DL(S) = L(S)?
>
> Mike told me that he thinks that case #1 and case #3 are impossible, but I
> don't know how to go about proving that. #2 is not possible for triads, but
> I don't know if it is possible for any other cases.

No, I didn't say that. Before I go off talking about what I did say,
can you tell me how you're defining "otonal" and "utonal" above?

-Mike

🔗Ryan Avella <domeofatonement@yahoo.com>

2/20/2012 5:31:50 PM

--- In tuning-math@yahoogroups.com, Mike Battaglia <battaglia01@...> wrote:
> No, I didn't say that. Before I go off talking about what I did say,
> can you tell me how you're defining "otonal" and "utonal" above?

I defined otonal and utonal the same way I defined them in my thread about ambitonal chords. If a chord has a smaller odd limit than its inverse, it is otonal. If it has a larger odd limit than its inverse, it is utonal. If the odd limits of the chord and its inverse are equal, they are ambitonal.

Ryan

🔗Mike Battaglia <battaglia01@gmail.com>

2/20/2012 5:53:32 PM

On Mon, Feb 20, 2012 at 8:31 PM, Ryan Avella <domeofatonement@yahoo.com>
wrote:
>
> --- In tuning-math@yahoogroups.com, Mike Battaglia <battaglia01@...>
> wrote:
> > No, I didn't say that. Before I go off talking about what I did say,
> > can you tell me how you're defining "otonal" and "utonal" above?
>
> I defined otonal and utonal the same way I defined them in my thread about
> ambitonal chords. If a chord has a smaller odd limit than its inverse, it is
> otonal. If it has a larger odd limit than its inverse, it is utonal. If the
> odd limits of the chord and its inverse are equal, they are ambitonal.

OK, so then the answer is:

1) Yes - 3:7:15:21 is an example

2) Yes - 3:5:9:15 is an example

3) Yes - 10:12:15 is an example

What I'd originally said was that I didn't think there was an example
for #1, so I was wrong about that. I thought that all such examples
would be either ambitonal or utonal.

-Mike

🔗Ryan Avella <domeofatonement@yahoo.com>

2/20/2012 8:13:17 PM

--- In tuning-math@yahoogroups.com, Mike Battaglia <battaglia01@...> wrote:
> OK, so then the answer is:
>
> 1) Yes - 3:7:15:21 is an example
>
> 2) Yes - 3:5:9:15 is an example
>
> 3) Yes - 10:12:15 is an example

Oh, okay sweet. So it is possible, then. But #1 and #2 are both impossible for triads, I suppose. That makes sense, since the outermost dyad must be reducible.

#3 doesn't look right though. The dyadic odd-limit (5) is smaller than the odd-limit (15), though I was looking for a utonal chord where DL(S) = L(S).

Ryan

🔗Mike Battaglia <battaglia01@gmail.com>

2/20/2012 8:56:05 PM

On Mon, Feb 20, 2012 at 11:13 PM, Ryan Avella <domeofatonement@yahoo.com>
wrote:
>
> --- In tuning-math@yahoogroups.com, Mike Battaglia <battaglia01@...>
> wrote:
> > OK, so then the answer is:
> >
> > 1) Yes - 3:7:15:21 is an example
> >
> > 2) Yes - 3:5:9:15 is an example
> >
> > 3) Yes - 10:12:15 is an example
>
> Oh, okay sweet. So it is possible, then. But #1 and #2 are both impossible
> for triads, I suppose. That makes sense, since the outermost dyad must be
> reducible.
>
> #3 doesn't look right though. The dyadic odd-limit (5) is smaller than the
> odd-limit (15), though I was looking for a utonal chord where DL(S) = L(S).
>
> Ryan

Oh, sorry, I wasn't reading carefully for #3. The answer for 3 is no, because:

Let S* be the inverse of S. Some initial lemmas:

1) DL(S*) = DL(S), because all of the dyads in S and S* are exactly the same.
2) DL(S) <= L(S), meaning that the odd-limit of any chord can never be
less than its dyadic limit.

I'll leave proving these up to you; I think if you think about them
for a second you'll see they make sense.

Now assume that some utonal chord U exists such that DL(U) = L(U). Thus

3) DL(U) = L(U) (assumption we're testing)
4) L(U) > L(U*). (your definition of utonal)
5) DL(U) > L(U*) (substitute 3 in 4)
6) DL(U*) > L(U*) (substitute 1 in 6)

But, DL(U*) can never be greater than L(U*), because because of #2,
for any chord S, DL(S) must be less than or equal to L(S). So we've
arrived at a contradiction, and no utonal chords can exist where DL(S)
= L(S).

-Mike