Dave Keenan asked for primes to be expressed in the miracle fourth

system; since this was an eminently reasonable querry I am

reproducing the results here. If A is 5/3, flat by one cent, and B is

4/3, sharp by 2 cents, then we have the following approximations:

2 = A^(-6) B^13

3 = A^(-12) B^25

5 = A^(-11) B^25

7 = A^14 B^(-18)

11 = A^3 B^3