update

>As far as I am concerned, this verifies the 1/sqrt(n*d) weighting rule for
>dyads. Now to verify, or find an alterative to, the 1/cuberoot(l*m*n) rule
>for triads, armed with the set of triads with l*m*n<1million that Graham
>sent me (thanks Graham!) This could take a lot of CPU cycles!

Any news yet?

-Carl

>>As far as I am concerned, this verifies the 1/sqrt(n*d) weighting rule for
>>dyads. Now to verify, or find an alterative to, the 1/cuberoot(l*m*n) rule
>>for triads, armed with the set of triads with l*m*n<1million that Graham
>>sent me (thanks Graham!) This could take a lot of CPU cycles!

>Any news yet?

I've gotten in touch with a friend at Fermilab. He might be able to do some
computations a lot faster than I could.